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The binary shift operators in C are defined via the change of their values, not the change of the memory representation of them. When reading a value from little endian out of buffer `buf`, `((uint16_t)buf[1] << 8) | buf[0]` will thus work regardless of the byte order of the host system. |
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| include | ||
| bmx280_saul.c | ||
| bmx280.c | ||
| Makefile | ||