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RIOT/sys/rtc_utils/rtc_utils.c

261 lines
6.6 KiB
C

/*
* Copyright (C) 2019 ML!PA Consulting GmbH
*
* This file is subject to the terms and conditions of the GNU Lesser General
* Public License v2.1. See the file LICENSE in the top level directory for more
* details.
*/
/**
* @ingroup sys_rtc_utils
* @{
*
* @file
* @brief common RTC helper functions
*
* @author Benjamin Valentin <benjamin.valentin@ml-pa.com>
*
* @}
*/
#include <stdint.h>
#include <stdlib.h>
#include <string.h>
#include "periph/rtc.h"
#ifndef RTC_NORMALIZE_COMPAT
#define RTC_NORMALIZE_COMPAT (0)
#endif
#define MINUTE (60U)
#define HOUR (60U * MINUTE)
#define DAY (24U * HOUR)
/*
* The rules here are (to be checked in that explicit order):
* 1. If the year is not a multiple of four, it is not a leap year.
* 2. If the year is a multiple of 400, it is a leap year
* 3. If the year is a multiple of 100, it is not a leap year.
*/
static int _is_leap_year(int year)
{
/* not a multiple of four, so not a leap year */
if (year & 0x3) {
return 0;
}
/*
* We know that year is a multiple of four by now. If it is also a multiple of 25,
* it is therefore a multiple of hundred. Thus (with year being a multiple of
* four), !!(year %25) is 0 if and only if year is a multiple of 100. !(year & 15)
* is 0 for all year that are not a multiple of 16.
*
* As !!(year %25) only returns 0 for years that are a multiple of 100 (out of all
* the multiples of four), || !(year &15) is only evaluated for these. Out of all
* multiples of 100, !(year &15) is 0 except for those that are a multiple of 400.
*/
return !!(year % 25) || !(year & 15);
}
/*
* 1. Every fourth year was a leap year.
* 2. Subtract all years divisible by 100, those are divisible by 4 but no leap years.
* 3. Add back all years divisible by 400, those are divisible by 100 but leap years.
*/
static unsigned _leap_years_before(unsigned year)
{
--year;
return (year / 4) - (year / 100) + (year / 400);
}
static unsigned _leap_years_since_epoch(unsigned year)
{
if (year < RIOT_EPOCH) {
return 0;
}
return _leap_years_before(year) - _leap_years_before(RIOT_EPOCH);
}
static int _month_length(int month, int year)
{
if (month == 1) {
return 28 + _is_leap_year(year);
}
/*
* From January (0) to July (6), with the exception of the already handled February
* (month == 1), the months have 31 and 30 days in turns. Thus, subtracting 1 da
* if the month is odd works here.
*
* From August (7) to December (11) again we have 31 and 30 days in turns. If we
* reset the counter at August (7) to 0, we can therefore again subtract 1 day if
* the month counter is odd. (month % 7) here is used to reset the counter to zero
* at August (7).
*/
return 31 - ((month % 7) & 1);
}
#if RTC_NORMALIZE_COMPAT
static int _wday(int day, int month, int year)
{
/* Tomohiko Sakamoto's Algorithm
* https://en.wikipedia.org/wiki/Determination_of_the_day_of_the_week#Sakamoto's_methods
*/
static const uint8_t t[] = {0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4};
year -= month < 2;
return (year + year/4 - year/100 + year/400 + t[month] + day) % 7;
}
#endif /* RTC_NORMALIZE_COMPAT */
static int _yday(int day, int month, int year)
{
/* Cumulative number of days since start of the year. In order to squeeze this into
8 bits, we wrap around at 255 and handle this later. */
static const uint8_t d[] = { 0, 31, 59, 90, 120, 151,
181, 212, 243, 17, 48, 78};
/* If year is a leap year, February (1) has an extra day. */
if (month > 1) {
day += _is_leap_year(year);
}
/* For months October (9), November (10), and December (11) number in d was wrapped
around to fit into 8 bits. We undo this now. */
if (month > 8) {
day |= 0x100;
}
/* subtract 1 as counting starts at zero, e.g.
2019-01-01 will be be day 0 in year 2019 */
return d[month] + day - 1;
}
void rtc_tm_normalize(struct tm *t)
{
div_t d;
if (t->tm_mday == 0) {
t->tm_mday = 1;
}
d = div(t->tm_sec, 60);
t->tm_min += d.quot;
t->tm_sec = d.rem;
d = div(t->tm_min, 60);
t->tm_hour += d.quot;
t->tm_min = d.rem;
d = div(t->tm_hour, 24);
t->tm_mday += d.quot;
t->tm_hour = d.rem;
d = div(t->tm_mon, 12);
t->tm_year += d.quot;
t->tm_mon = d.rem;
/* Loop to handle days overflowing the month. */
while (1) {
int days = _month_length(t->tm_mon, t->tm_year + 1900);
if (t->tm_mday <= days) {
break;
}
if (++t->tm_mon > 11) {
t->tm_mon = 0;
++t->tm_year;
}
t->tm_mday -= days;
}
#if RTC_NORMALIZE_COMPAT
t->tm_yday = _yday(t->tm_mday, t->tm_mon, t->tm_year + 1900);
t->tm_wday = _wday(t->tm_mday, t->tm_mon, t->tm_year + 1900);
#endif
}
uint32_t rtc_mktime(struct tm *t)
{
unsigned year = t->tm_year + 1900;
uint32_t time = t->tm_sec
+ t->tm_min * MINUTE
+ t->tm_hour * HOUR
+ _yday(t->tm_mday, t->tm_mon, year) * DAY;
unsigned leap_years = _leap_years_since_epoch(year);
unsigned common_years = (year - RIOT_EPOCH) - leap_years;
time += (leap_years * 366 + common_years * 365) * DAY;
return time;
}
void rtc_localtime(uint32_t time, struct tm *t)
{
uint32_t y_secs = _is_leap_year(RIOT_EPOCH) ? (366 * DAY) : (365 * DAY);
unsigned year = RIOT_EPOCH;
while (time > y_secs) {
time -= y_secs;
++year;
y_secs = _is_leap_year(year) ? (366 * DAY) : (365 * DAY);
}
memset(t, 0, sizeof(*t));
t->tm_sec = time;
t->tm_year = year - 1900;
rtc_tm_normalize(t);
}
#define RETURN_IF_DIFFERENT(a, b, member) \
if (a->member != b->member) { \
return a->member-b->member; \
}
int rtc_tm_compare(const struct tm *a, const struct tm *b)
{
RETURN_IF_DIFFERENT(a, b, tm_year);
RETURN_IF_DIFFERENT(a, b, tm_mon);
RETURN_IF_DIFFERENT(a, b, tm_mday);
RETURN_IF_DIFFERENT(a, b, tm_hour);
RETURN_IF_DIFFERENT(a, b, tm_min);
RETURN_IF_DIFFERENT(a, b, tm_sec);
return 0;
}
bool rtc_tm_valid(const struct tm *t)
{
if (t->tm_sec < 0) {
return false;
}
if (t->tm_min < 0) {
return false;
}
if (t->tm_hour < 0) {
return false;
}
if (t->tm_mday < 0) {
return false;
}
if (t->tm_mon < 0) {
return false;
}
if (t->tm_year < 0) {
return false;
}
struct tm norm = *t;
rtc_tm_normalize(&norm);
return rtc_tm_compare(t, &norm) == 0;
}