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make: dedup USEMODULE_INCLUDES w/o shelling out

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Currently, `USEMODULE_INCLUDES` is deduplicated using a combination of
`tr` and `awk`. The proposed method achieves a deduplication (no
sorting) without the need to shell out by using make internals only.
This commit is contained in:
Cenk Gündoğan 2018-07-03 11:36:41 +02:00
parent 6244ce4f4e
commit 202e73dcdf
1 changed files with 9 additions and 1 deletions
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10
Makefile.include
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@ -327,7 +327,15 @@ $(info $(USEPKG:%=$(RIOTPKG)/%/Makefile.include))
.PHONY: $(USEPKG:%=$(RIOTPKG)/%/Makefile.include) .PHONY: $(USEPKG:%=$(RIOTPKG)/%/Makefile.include)
-include $(USEPKG:%=$(RIOTPKG)/%/Makefile.include) -include $(USEPKG:%=$(RIOTPKG)/%/Makefile.include)
USEMODULE_INCLUDES_ = $(shell echo $(USEMODULE_INCLUDES) | tr ' ' '\n' | awk '!a[$$0]++' | tr '\n' ' ') # Deduplicate includes without sorting them
# see https://stackoverflow.com/questions/16144115/makefile-remove-duplicate-words-without-sorting
define uniq =
$(eval seen :=)
$(foreach _,$1,$(if $(filter $_,$(seen)),,$(eval seen += $_)))
$(seen)
endef
USEMODULE_INCLUDES_ = $(strip $(call uniq,$(USEMODULE_INCLUDES)))
INCLUDES += $(USEMODULE_INCLUDES_:%=-I%) INCLUDES += $(USEMODULE_INCLUDES_:%=-I%)