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make: allow for disabling colored compiler output

This commit is contained in:
Hauke Petersen 2017-08-07 10:20:30 +02:00
parent 31207400e8
commit 09ab7cb0a8

View File

@ -25,9 +25,13 @@ ifeq ($(shell $(CC) -fno-delete-null-pointer-checks -E - 2>/dev/null >/dev/null
endif
endif
# Use colored gcc output if the compiler supports this
ifeq ($(shell $(CC) -fdiagnostics-color -E - 2>/dev/null >/dev/null </dev/null ; echo $$?),0)
CFLAGS += -fdiagnostics-color
# Use colored compiler output if the compiler supports this and if this is not
# disabled by the user
CC_NOCOLOR ?= 0
ifeq ($(CC_NOCOLOR),0)
ifeq ($(shell $(CC) -fdiagnostics-color -E - 2>/dev/null >/dev/null </dev/null ; echo $$?),0)
CFLAGS += -fdiagnostics-color
endif
endif
# Fast-out on old style function definitions.